A. Objective The learners should be able to investigate changes that happen in the absence of oxygen. B. Materials ● fire. Activity: TITLE: ABSENCE OF OXYGEN Jar with cover (Jar A) Jar without cover (Jar B) 2 same sized candle (small) Match or lighter Timer Ruler C. Precautionary Measure Remember to handle match or lighter carefully and don't play with it for it can cause D. Procedure 1. Label the jar with cover with Jar A and the jar without cover as Jar B. 2. Light the candles with a match and put the candles in each jar. 3. Record the time when the candles are lighted and the time when the light was put off. 4. Cover the Jar A and observe what will happen. 5. Measure the length of the candles after the flame was put off. 6. Record your findings on the chart below. Jars JAR A JAR B Time of the flame was put off Length of the candle after burning Answer the following questions: 1. Which of the 2 jars was the candle's flame put off first? 2. Which of the two candles has the shortest size? 3. What happen, when you cover the Jar A? 4. When the lighted candle in Jar A was covered, the flame was put off, what is the reason why the candle's flame did not continue to burn? 5. What are the 3 main components in combustion? Doss​

Evaluate the given interges

a. (-5) + (-4) =
b. (-4) (7) =
c. 6 - (-2) =
d. (-3) + 1 =
e. (-18) ÷ (-6)=
f. (-1) • (5) =
g (-2) (7) =
h. (8) (3) =
i. 9 + (-3) =
j. (-4) - (-1)

[tex]\LARGE\tt✏PA \:BRAINLIEST :[/tex]

[tex]\LARGE\tt✏PROBLEM :[/tex]

Evaluate the given interges

a. (-5) + (-4) =

b. (-4) (7) =

c. 6 - (-2) =

d. (-3) + 1 =

e. (-18) ÷ (-6)=

f. (-1) • (5) =

g (-2) (7) =

h. (8) (3) =

i. 9 + (-3) =

j. (-4) - (-1)

[tex]\LARGE\tt✏ANSWER :[/tex]

Let's evaluate the given integer expressions:

a. (-5) + (-4) = -9

When adding two negative numbers, you add their absolute values and keep the negative sign.

b. (-4) * (7) = -28

When multiplying one negative number with a positive number, the product will be negative.

c. 6 - (-2) = 8

Subtracting a negative number is equivalent to adding its absolute value. So, 6 - (-2) is the same as 6 + 2.

d. (-3) + 1 = -2

Adding a negative number and a positive number results in a negative sum.

e. (-18) ÷ (-6) = 3

Dividing a negative number by another negative number results in a positive quotient.

f. (-1) * (5) = -5

Multiplying a negative number by a positive number gives a negative product.

g. (-2) * (7) = -14

Multiplying two negative numbers results in a positive product.

h. (8) * (3) = 24

The product of two positive numbers is positive.

i. 9 + (-3) = 6

Adding a positive number and a negative number gives the sum.

j. (-4) - (-1) = -3

Subtracting a negative number from a negative number is the same as adding the absolute values. So, (-4) - (-1) equals (-4) + 1, which is -3.

These are the results of evaluating the given integer expressions.

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