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given the following polynomial function draw the graph of each pair in the coordinate plane1. a. y= (x+2) (x-3) (x+6) (x+3)b. y= -(x-1) (x-2)² (x+1)(x-3)²2. a. y= (x+3) (x+6) (2x+1)b. y= (x-1)= (2x-3) (2x+1) (x+2)please if your going to answer sana po related sa questions, rlly appreciate it thankyou^^
given the following polynomial function draw the graph of each pair in the coordinate plane
1. a. y= (x+2) (x-3) (x+6) (x+3)
b. y= -(x-1) (x-2)² (x+1)(x-3)²
2. a. y= (x+3) (x+6) (2x+1)
b. y= (x-1)= (2x-3) (2x+1) (x+2)
please if your going to answer sana po related sa questions, rlly appreciate it thankyou^^
TO GRAPH FIND THE X AND Y INTERCEPT :
TO FIND THE X-INTERCEPT MAKE Y = 0 AND
TO FIND THE Y-INTERCEPT MAKE X = 0
1.)
- a. y = (x+2)(x-3)(x+6)(x+3)
FOR X-INTERCEPT :
0 = (x+2)(x-3)(x+6)(x+3) = -2, 3, -6, -3
X-INTERCEPT : (-2,0), (3,0), (-6,0), (-3,0)
FOR Y-INTERCEPT :
y = (0+2)(0-3)(0+6)(0+3) = (2)(-3)(6)(3) = -108
Y-INTERCEPT : (0,-108)
- b. y = -(x-1)(x-2)²(x+1)(x-3)²
FOR X-INTERCEPT :
0 = -(x-1)(x-2)²(x+1)(x-3)² = 1, 2, -1, 3
X-INTERCEPT : (1,0), (2,0), (-1,0), (3,0)
FOR Y-INTERCEPT :
y = -(0-1)(0-2)²(0+1)(0-3)² = (1)(4)(1)(9) = 36
Y-INTERCEPT : (0,36)
2.)
- a. y = (x+3)(x+6)(2x+1)
FOR X-INTERCEPT :
0 = (x+3)(x+6)(2x+1) = -3, -6, -1/2
X-INTERCEPT : (-3,0), (-6,0), (-1/2,0)
FOR Y-INTERCEPT : (
y = (0+3)(0+6)(2(0)+1) = (3)(6)(1) = 18
Y-INTERCEPT : (0,18)
- b. y = (x-1)(2x-3)(2x+1)(x+2)
FOR X-INTERCEPT :
0 = (x-1)(2x-3)(2x+1)(x+2) = 1, 3/2, -1/2, -2
X-INTERCEPT : (1,0), (3/2,0), (-1/2,0), (-2,0)
FOR Y-INTERCEPT :
y = (0-1)(2(0)-3)(2(0)+1)(0+2) = (-1)(-3)(1)(2) = 6
Y-INTERCEPT : (0,6)
TO ANSWER THIS KIND OF PROBLEM
STUDY THE FOLLOWING :
- GRAPH OF POLYNOMIAL FUNCTION
- X-INTERCEPT AND Y-INTERCEPT
- CARTESIAN COORDINATE PLANE
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