A. Objective The learners should be able to investigate changes that happen in the absence of oxygen. B. Materials ● fire. Activity: TITLE: ABSENCE OF OXYGEN Jar with cover (Jar A) Jar without cover (Jar B) 2 same sized candle (small) Match or lighter Timer Ruler C. Precautionary Measure Remember to handle match or lighter carefully and don't play with it for it can cause D. Procedure 1. Label the jar with cover with Jar A and the jar without cover as Jar B. 2. Light the candles with a match and put the candles in each jar. 3. Record the time when the candles are lighted and the time when the light was put off. 4. Cover the Jar A and observe what will happen. 5. Measure the length of the candles after the flame was put off. 6. Record your findings on the chart below. Jars JAR A JAR B Time of the flame was put off Length of the candle after burning Answer the following questions: 1. Which of the 2 jars was the candle's flame put off first? 2. Which of the two candles has the shortest size? 3. What happen, when you cover the Jar A? 4. When the lighted candle in Jar A was covered, the flame was put off, what is the reason why the candle's flame did not continue to burn? 5. What are the 3 main components in combustion? Doss​

Activity 4 LET'S SOLVE IT... Directions: Calculate the mean, median and mode of the weight of IV-2 Students. Write your complete solutions and answers in a sheet of paper. Weight of IV-2 Students Weight in kg Frequency 75-79 1 70-74 4 65-69 10 60-64 14 55-59 21 50-54 15 45-69 14 40-44 1 Mean Median = Mode​

Answer:

Mean: 57.25 kg

Median: within the range of 55-59 kg

Mode: within the range of 55-59 kg

Step-by-step explanation:

Mean:

To find the mean, we calculate the midpoint for each weight class by averaging the lower and upper boundaries, then multiply each midpoint by the class frequency, sum these products, and divide by the total number of students.

Calculate the midpoints for each class:

75-79: (75+79)/2 = 77

70-74: (70+74)/2 = 72

65-69: (65+69)/2 = 67

60-64: (60+64)/2 = 62

55-59: (55+59)/2 = 57

50-54: (50+54)/2 = 52

45-49: (45+49)/2 = 47

40-44: (40+44)/2 = 42

Multiply midpoints by frequencies and sum them:

(771) + (724) + (6710) + (6214) + (5721) + (5215) + (4714) + (421)

Calculate the total number of students by summing the frequencies:

1+4+10+14+21+15+14+1 = 80 (assuming the typo is corrected)

Divide the sum of the midpoint-frequency products by the total number of students:

Mean = (771 + 724 + 6710 + 6214 + 5721 + 5215 + 4714 + 421) / 80

Median:

The median is the value that separates the higher half from the lower half of the data set. Since there are 80 students, the median would be the average of the 40th and 41st values.

Count up the frequencies to find the classes that contain the 40th and 41st values.

Since the cumulative frequency reaches 40 at the 55-59 kg class, the median lies within this class.

Mode:

The mode is the value that appears most frequently. In a grouped frequency distribution, the mode is the class with the highest frequency.

Look for the class with the highest frequency, which is 55-59 kg with a frequency of 21.

Now, let's calculate the actual numbers:

Mean:

= (771 + 724 + 6710 + 6214 + 5721 + 5215 + 4714 + 421) / 80

= (77 + 288 + 670 + 868 + 1197 + 780 + 658 + 42) / 80

= 4580 / 80

= 57.25 kg